Factorisez en reconnaissant la différence de deux carrés: A=x²-9+(x+3)²; B=(x-2)²-(x²-4); C=(2x+3)(x+1)+4x²-9; D=(x+1)²-(x-)²; E=(x+1)²-9; F=16-(x-1)²; G=(2x-5)
Mathématiques
moha773
Question
Factorisez en reconnaissant la différence de deux carrés:
A=x²-9+(x+3)²;
B=(x-2)²-(x²-4);
C=(2x+3)(x+1)+4x²-9;
D=(x+1)²-(x-)²;
E=(x+1)²-9;
F=16-(x-1)²;
G=(2x-5)²-(2x+3²;
A=x²-9+(x+3)²;
B=(x-2)²-(x²-4);
C=(2x+3)(x+1)+4x²-9;
D=(x+1)²-(x-)²;
E=(x+1)²-9;
F=16-(x-1)²;
G=(2x-5)²-(2x+3²;
1 Réponse
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1. Réponse Anonyme
A=x²-9+(x+3)²;
= (x-3)(x+3)-(x+3)²
= (x+3)(x-3-x-3)
= (x-3)(-6)
= -6(x-3)
B=(x-2)²-(x²-4);
=(x-2)²-(x-2)(x+2)
= (x-2)(x-2-x-2)
= (x-2)(-4)
= -4(x-2)
C=(2x+3)(x+1)+4x²-9;
= (2x+3)(x+1)+(2x-3)(2x+3)
= (2x+3)(x+1-2x+3)
= (2x+3)(-x+4)
D=(x+1)²-(x-?)²;
= manque
E=(x+1)²-9;
= (x-1-3)(x-1+3)
= (x-4)(x+2)
F=16-(x-1)²;
= (4-x+1)(4+x-1)
= (-x+5)(x+3)
G=(2x-5)²-(2x+3)²
=(2x-5-2x-3)(2x-5+2x+3)
= -8(4x-2)
= -16(2x-1)