aidez moi svp factoriser les expressions suivantes: = -5(2-4)+(2-4)(+3) = (-7)(3-5)-(3-5)(2-9) ℂ= (-4+1)(+2)-(-4+1)aux carre =(6-5)(-4)+(6-5) =(3-6)(+8)+(-2)(2-

Réponse :

Explications étape par étape

Bonsoir

factoriser les expressions suivantes:

= -5(2-4)+(2-4)(+3)

= (2 - 4)(-5 + 3)

= (-6)(-2)

= 12

= (-7)(3-5)-(3-5)(2-9)

= (3 - 5)(-7 - 2 + 9)

= (3 - 5)(-9 + 9)

= (-2) * 0

= 0

ℂ= (-4+1)(+2)-(-4+1)aux carre

= (-4 + 1)(2 + 4 - 1)

= (-3)(6 - 1)

= (-3) * 5

= (-15)

=(6-5)(-4)+(6-5)

= (6 - 5)(-4 + 1)

= 1 * (-3)

= (-3)

=(3-6)(+8)+(-2)(2-5)​

= 2[4(3 - 6) - 2 + 5]

= 2(4 * (-3) + 3)

= 2(-12 + 3)

= 2 * (-9)

= (-18)